2010.09.21 previous lecture note                                                  2010.09.28 next lecture note

HELIUM -PART 3

0-He-coordinates.png

The spectrum of helium. For the first column - the singlet and triplet parts are separated.
To the right is the case when one electron is free.
The original picture is in the EXAM SLIDES
Doubly excited states - the electrons would be bound, but because of their repulsion
the total energy is high so that one electron can be ejected.
Thus we get autoionizing states
a-1-excited-helium.png

Part of the table - just for helium. This is about the role of the 'perturbation term' 5/8 Z E0
a-2-Perturbation-He-table.png

The whole table, with only perturbation part
a-3-Perturbation-table.png

Evaluation of the repulsion - the multipole expansion
b1-repulsion.png

Spherical harmonics integral - for ground state we only need one term - all three zeros
         b2-repulsion.png


b3-repulsion.png


b4-repulsion.png

Done - perturbation theory for the ground state. How is it for the excited states, when antisymmetric functions
must be used

d-1-perturbation-excited-state.png

This is originally from the many-electron atoms EXAM SLIDES
excited states, when antisymmetric functions   must be used
d-15-excited-state-evaluate.png

VARIATIONAL METHOD FOR GROUND STATE OF HELIUM
d-2-variational-1.png


d-3-variational-2.png

LATER WE SHALL USE A SLIGHTLY more free theory - without assumed normalization.
That is important to get "variational principle for Schrödinger equation" - this all later
d-4-variational-2.png

Details of the variational calculation
d-4-variational.png


d-6-variational.png


d-7-variational.png
The final results are summarized in the table which is in the EXAM SLIDES.
It can also be obtained from the spreadsheet (we have both xls (microsoft)  - and ods (the world- OpenOffice) formats (advice: use ODS, OpenOffice)
You can also see the HTML version for quick information (without the calculations).

SUMMARY OF HELIUM
q4.png


q5.png

The case of disappearing excited state.
A circle can not have first excited state - it has an infinite excitation energy
                  q6.png

As the rotator gets 2 identical ends, three, four and then general N corners (balls),
the region of variable phi shrinks from 2pi to pi (N=2),  2pi/3 (N=3) etc.
Consequently, the first excited state gets HIGHER and HIGHER
                        q7.png


                                     q8.png
This is an illustration of what the "identical" and "symmetry" can mean: it means eliminating the regions of variable(s)
which are not physical (i.e. not a part of the consistent model)

NEXT: 
MANY ELECTRON ATOMS

2010.09.21 previous lecture note                                                  2010.09.28 next lecture note